A 6.60 uC particle moves through a region of space where an electric field of magnitude 1200 N/C points in the positive x direction and a magnetic field of magnitude 1.02T points in the positive z direction.
If the net force acting on the particle is 6.21x10^-3 N, in the positive x direction, find the components of the particle's velocity. Assume the particle's velocity is the x-y plane.
vx , vy , vz =
I just know we use the formulas:
F =qE
F=qvB
I can't figure how to get the velocities for the 3 components...
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Since the electric force is greater than net force (while both point to the right), the magnetic force must be to the left. The charge is positive, magnetic field B out paper, so the velocity points downward (negative y). The v of other components are zero
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