The capacitor in an circuit ( = 140 , = 40 ) is initially uncharged.
PartB
Find the current in the circuit one time constant after the circuit is connected to a 9.0- battery.
I use this but didnt work
I = V/R (1-e^-t/RC)
When the problem said one time constant, does that always mean that t/RC = 1, or only the RC is equal to 1?
I think Prof gave the similar problem on the last quiz, where it asked the current after 2 time constant. And he just plugged the "2" into t/RC
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so one time constant means that t = RC. What did you put for the time?
ReplyDeleteI = 9V / 140 ohms (1-e^-1)
ReplyDeleteand I got 41mA but that's not the correct answer.
Part A asks the charge, I did similar thing and it worked
q = 40 * 9V (1-e^-1)
= 230 microC, and that's right
Finally I got that.
ReplyDeleteDidnt realize the equation was wrong
it should be I= V/R (e^t/RC)
instead of I= V/R (1-e^t/RC)