for this problem do we just plug in the values into the formula:
q(t) = C(emf) (1 - e^ (-t/T) ??
for some reason it isn't working out for me..
emf = 9V
R = 50.0 k Olms
C - 140 mF
it wants to find the time (t) it takes to charge the capacitor to 5.0V.
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I think what you have to do is use this equation:
ReplyDeleteV=Vo(1-e^-t/T)
Where V is 5.0 V and Vo is the 9.0 V. If you use that instead of q(t) and C(emf) it should work to solve for t... hope that helps!
So if it wants you to find the time to CHARGE the capacitor to 5.0 V what would the initial voltage, Vo be?
ReplyDeleteThis comment has been removed by the author.
ReplyDeletei'm getting about 5.7 x 10^3 sec, but it is saying it is wrong.
ReplyDeletei kept the kOhm cuz it wants the time in seconds and not mS.
can't figure out what i'm doing wrong
when you say " the initial voltage" you're talking about the initial voltage of the capacitor before it is charged? shouldnt it be at zero (Vo = 0) ?
ReplyDeleteso the problem would be:
5.0 = 0.0 (1-e^-t/T)
my math is rusty but doesnt that not work? xD