A parallel plate vacuum capacitor is connected to a battery and charged until the stored electric energy is U. The batter is removed and then a dielectric material with dielectric constant k is insterted into the capacitor, filling the space between the places. Finally, the capacitor is fully discharged through a resistor (which is connected across the capacitor terminals)
a. )Find "Ur " the energy dissipated in the resistor Express your answer in terms of "U" and other given quantities.
b.) Consider the same situation as in the previous part, except that the charging battery remains connected while the dielectric is inserted. The battery is then disconnected and the capacitor is discharged. For this situation, what is "Ur" , the energy dissipated in the resistor. Express the answer in therms of U and other given quantities.
im a little confused, the resistor is throwing me off. How do i approach this problem?? How do i answer these in terms of "U"?
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oh figured it out, he went over this in class
ReplyDeleteso you are good?
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